Difference between revisions of "Magnetodynamics with cohomology conditions"

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[[File:indheatdomaincond.jpg|400px|frameless|alt=Boundary conditions|Applied boundary conditions.]]
 
[[File:indheatdomaincond.jpg|400px|frameless|alt=Boundary conditions|Applied boundary conditions.]]
  
−
Note that the boundary $\partial M$ is now decomposed on two parts according to the boundary condition applied on it: $\partial M = S_1 \cap S_2$. On $S_1 = M_c \cap \partial M$ we have the condition $\vec{e} \times \vec{n} = 0$ and on $S_2 = M_a \cap \partial M$ we have the condition $\vec{j} \cdot \vec{n} = 0$. We can either drive the problem by the net current through the terminals, or by the net voltage between the terminals:
+
Note that the boundary $\partial M$ is now decomposed on two parts according to the boundary condition applied on it: $\partial M = S_1 \cap S_2$. On $S_1 = M_c \cap \partial M$ we have the condition $\vec{e} \times \vec{n} = 0$ and on $S_2 = M_a \cap \partial M$ we have the condition $\vec{j} \cdot \vec{n} = 0$. We can either drive the problem by the net current $I_s$ through the terminals, or by the net voltage difference $V_s$ between the terminals:
 
\begin{align}  
 
\begin{align}  
−
\int_{c} \vec{e} \cdot \mathrm{d} \vec{l} &= V_s, \label{eq:vs} \\
+
\int_{\zeta} \vec{e} \cdot \mathrm{d} \vec{l} &= V_s, \label{eq:vs} \\
−
\int_S \vec{j} \cdot \vec{n} \, \mathrm{d} a  = \int_{\partial S} \vec{h} \cdot \mathrm{d} \vec{l} &= I_s, \label{eq:is} \\
+
\int_{\Sigma} \vec{j} \cdot \vec{n} \, \mathrm{d} a  = \int_{\partial \Sigma} \vec{h} \cdot \mathrm{d} \vec{l} &= I_s, \label{eq:is} \\
 
\end{align}
 
\end{align}
−
where $c$ is a path on $\partial M$ between the terminals on $S_1$ and $S$ is a surface that isolates the terminals. The boundary $\partial S$ also lies on the boundary of the domain $\partial M$. In addition, the fields $\vec{e}$ and $\vec{j}$ are linked by the constitutive equation $\vec{e} = \rho \vec{j}$. All these considerations hint a duality between the electric field $\vec{e}$ and the current density $\vec{j}$.
+
where $\zeta$ is a path on $\partial M$ between the terminals on $S_1$ and $\Sigma$ is a surface that isolates the terminals. The boundary $\partial \Sigma$ also lies on the boundary of the domain $\partial M$. In addition, the fields $\vec{e}$ and $\vec{j}$ are linked by the constitutive equation $\vec{e} = \rho \vec{j}$. All these considerations hint a duality between the electric field $\vec{e}$ and the current density $\vec{j}$.
  
 
=== $T-\Omega$ potential formulation ===
 
=== $T-\Omega$ potential formulation ===

Revision as of 09:25, 10 January 2013

\(\renewcommand{\vec}[1]{\mathbf{#1}} \newcommand{\Grad}[1]{\mathbf{\text{grad}}\,{#1}} \newcommand{\Curl}[1]{\mathbf{\text{curl}}\,{#1}} \newcommand{\Div}[1]{\text{div}\,{#1}} \newcommand{\Real}[1]{\text{Re}({#1})} \newcommand{\Imag}[1]{\text{Im}({#1})} \newcommand{\pvec}[2]{{#1}\times{#2}} \newcommand{\psca}[2]{{#1}\cdot{#2}} \newcommand{\E}[1]{\,10^{#1}} \newcommand{\Ethree}{{\mathbb{E}^3}} \newcommand{\Etwo}{{\mathbb{E}^2}} \newcommand{\Units}[1]{[\mathrm{#1}]} \)Here we represent and induction heating eddy current problem that utilizes the homology and cohomology solver of Gmsh.

Problem definition

The domain

Let $M \subset \mathbb{R}^3$ and let $\partial M = S_1 \cup S_2$ so that $\partial S_1 = \partial S_2 = S_1 \cap S_2$ denote the 3D modeling domain and its 2D boundary that is decomposed in two parts. Furthermore, the domain $M$ is decomposed in a conducting subdomain $M_c$ and a non-conducting subdomain $M_a$ so that $M = M_c \cup M_a$ and $M_c \cap M_a = \partial M_c \cap \partial M_a$ hold. We assume that $M$ is connected and has no holes nor voids, i.e. its Betti numbers are $b_0(M)$ = 1 and $b_1(M) = b_2(M) = 0$.

Topology of the modeling domain.

The boundary value problem

We solve time harmonic magnetoquasistatic approximation to the Maxwell's equations in $M$:

\begin{align} \Curl{\vec{h}} &= \vec{j}, \label{eq:ampere}\\ \Curl{\vec{e}} + i \omega \vec{b} &= 0 , \label{eq:faraday}\\ \Div{\vec{b}} &= 0 , \label{eq:gaussm}\\ \end{align} with constitutive equations \begin{align} \vec{b} &= \mu \vec{h} \label{eq:bmuh} , \\ \vec{e} &= \rho \vec{j} \label{eq:erhoj} . \end{align}

In order to treat the domain $M$ as a circuit element, we apply magnetic isolation at its boundary $\partial M$. This is achieved by the boundary condition \begin{align} \vec{b} \cdot \vec{n} = 0 \textrm{ on } \partial M. \label{eq:bn} \end{align}

In the non-conducting domain $M_a$ we have no currents: \begin{align} \Curl{\vec{h}} = 0 \textrm{ in } M_a, \label{eq:dh} \end{align} and the current does not pass from the conducting domain $M_c$ to the non-conducting domain $M_a$. Also, the current cannot pass through the boundary $\partial M$ to the non-conducting domain $M_a$. These considerations result the conditions \begin{align} \vec{j} \cdot \vec{n} = 0 \textrm{ on } \partial M_a \cap \partial M_c \textrm{ and on } M_a \cap \partial M \label{eq:jn} \end{align} is required to hold at their interface. The terminals on $M_c \cap \partial M$ which connect the inductor coil to an external circuit are modeled as equipotential surfaces, i.e. as perfectly conducting surfaces. Thus, we apply a boundary condition \begin{align} \vec{e} \times \vec{n} = 0 \textrm{ on } M_c \cap \partial M. \label{eq:et} \end{align}

Applied boundary conditions.

Note that the boundary $\partial M$ is now decomposed on two parts according to the boundary condition applied on it: $\partial M = S_1 \cap S_2$. On $S_1 = M_c \cap \partial M$ we have the condition $\vec{e} \times \vec{n} = 0$ and on $S_2 = M_a \cap \partial M$ we have the condition $\vec{j} \cdot \vec{n} = 0$. We can either drive the problem by the net current $I_s$ through the terminals, or by the net voltage difference $V_s$ between the terminals: \begin{align} \int_{\zeta} \vec{e} \cdot \mathrm{d} \vec{l} &= V_s, \label{eq:vs} \\ \int_{\Sigma} \vec{j} \cdot \vec{n} \, \mathrm{d} a = \int_{\partial \Sigma} \vec{h} \cdot \mathrm{d} \vec{l} &= I_s, \label{eq:is} \\ \end{align} where $\zeta$ is a path on $\partial M$ between the terminals on $S_1$ and $\Sigma$ is a surface that isolates the terminals. The boundary $\partial \Sigma$ also lies on the boundary of the domain $\partial M$. In addition, the fields $\vec{e}$ and $\vec{j}$ are linked by the constitutive equation $\vec{e} = \rho \vec{j}$. All these considerations hint a duality between the electric field $\vec{e}$ and the current density $\vec{j}$.

$T-\Omega$ potential formulation

$A-V$ potential formulation

Implementation

Indheat.geo: problem geometry and cohomology computation in Gmsh

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Direct link to file `Magnetodynamics/GMSH_GETDP/indheat.geo'

Indheat.pro: weak formulation in GetDP

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Direct link to file `Magnetodynamics/GMSH_GETDP/indheat.pro'

How to use

All the files (.geo and .pro) must be located in the same directory.

Meshing the domain and computing the cohomology

Go to the directory and then type: 

gmsh indheat.geo -3

After the mesh is built, a file "indheat.msh" should have been created in the directory.

Solving the problem with GetDP

In a Terminal, type (in the right directory) 

getdp indheat.pro -solve MagDynTOComplex -pos MagDynTO

to solve with $T-\Omega$ formulation, or 

getdp indheat.pro -solve MagDynAVComplex -pos MagDynAV

to solve with $A-V$ formulation.

Showing the result

Open the file "jTO.pos" or "jAV.pos" with Gmsh by typing "gmsh jTO.pos" or "gmsh jAV.pos" in a terminal in the right directory.

Result

Boundary mesh of the conducting regions. Current density in the conducting regions.

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